0=2w^2+4w-70

Solution for 0=2w^2+4w-70 equation:

0=2w^2+4w-70

We move all terms to the left:

0-(2w^2+4w-70)=0

We add all the numbers together, and all the variables

-(2w^2+4w-70)=0

We get rid of parentheses

-2w^2-4w+70=0

a = -2; b = -4; c = +70;
Δ = b2-4ac
Δ = -42-4·(-2)·70
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-24}{2*-2}=\frac{-20}{-4}
=+5
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+24}{2*-2}=\frac{28}{-4}
=-7
$